Home
О нас
Products
Services
Регистрация
Войти
Поиск
Ирина155
@Ирина155
July 2022
1
3
Report
Помогите решить пожалуйста.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
m11m
Verified answer
ОДЗ: x+2>0 x-6>0
x> -2 x>6
x∈(6; +∞)
(√(x+2) - √(x-6))²=2²
x+2-2√[(x+2)(x-6)]+x-6=4
2x-4-2√(x²+2x-6x-12)=4
-2√(x²-4x-12)=4+4-2x
-2√(x²-4x-12)=8-2x
2√(x²-4x-12)=2x-8
√(x²-4x-12)=x-4
x²-4x-12=(x-4)²
x²-4x-12=x²-8x+16
x²-x²-4x+8x=16+12
4x=28
x=7
Ответ: 7.
0 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите решить пожалуйста..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
ОДЗ: x+2>0 x-6>0x> -2 x>6
x∈(6; +∞)
(√(x+2) - √(x-6))²=2²
x+2-2√[(x+2)(x-6)]+x-6=4
2x-4-2√(x²+2x-6x-12)=4
-2√(x²-4x-12)=4+4-2x
-2√(x²-4x-12)=8-2x
2√(x²-4x-12)=2x-8
√(x²-4x-12)=x-4
x²-4x-12=(x-4)²
x²-4x-12=x²-8x+16
x²-x²-4x+8x=16+12
4x=28
x=7
Ответ: 7.