2x+1 = t ---> x = (t-1) / 2 ---> 4*x = 2*(t-1)
f(t) = 2*(t-1) + 5 = 2t - 2 + 5 = 2t + 3
f(x) = 2x + 3
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2x+1 = t ---> x = (t-1) / 2 ---> 4*x = 2*(t-1)
f(t) = 2*(t-1) + 5 = 2t - 2 + 5 = 2t + 3
f(x) = 2x + 3
Verified answer
F(2x+1)=4x+5=2(2x+2)+1f(x)=2x+2