Ответ:
Пошаговое объяснение:
sin²β + cos²β = 1 ⇒ sin²(π/7) + cos²(π/7) = 1
1- cos²(30°) = 1-(√3/2)²= 1 - 3/4 = 1/4
1 - sin²(60°) = 1 - (√3/2)²= 1 - 3/4 = 1/4
ygβ * ctgβ = 1 ⇒ tg(5π/6) * ctg(5π/6) = 1
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Ответ:
Пошаговое объяснение:
sin²β + cos²β = 1 ⇒ sin²(π/7) + cos²(π/7) = 1
1- cos²(30°) = 1-(√3/2)²= 1 - 3/4 = 1/4
1 - sin²(60°) = 1 - (√3/2)²= 1 - 3/4 = 1/4
ygβ * ctgβ = 1 ⇒ tg(5π/6) * ctg(5π/6) = 1