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albinasupper204
@albinasupper204
August 2022
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Vasily1975
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При n=5 S5=b1*((-1/3)⁵-1)/(-1/3-1)=b1*(-1/243-1)/(-4/3)=b1*(-244/243)/(-4/3)=b1*244*3/(243*4)=b1*61/81=61/3, откуда b1=61/3*(81/61)=81/3=27. Тогда bn=b1*(-1/3)ⁿ⁻¹, и при n=5 b5=27*(-1/3)⁴=27*1/81=1/3.
Ответ: b1=27, b5=1/3.
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Verified answer
При n=5 S5=b1*((-1/3)⁵-1)/(-1/3-1)=b1*(-1/243-1)/(-4/3)=b1*(-244/243)/(-4/3)=b1*244*3/(243*4)=b1*61/81=61/3, откуда b1=61/3*(81/61)=81/3=27. Тогда bn=b1*(-1/3)ⁿ⁻¹, и при n=5 b5=27*(-1/3)⁴=27*1/81=1/3.Ответ: b1=27, b5=1/3.