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yellok $\frac{1}{5a} - \frac{25a^{2}-4}{10a} + \frac{5a}{2} = \frac{2-25a^{2}+4+25a^{2}}{10a} = \frac{6}{10a} = \frac{3}{5a}$
$a= \frac{1}{3} \\ \frac{3}{5a}=\frac{3}{5*\frac{1}{3} }=\frac{9}{5}$

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233334 $\frac{1}{5a}-\frac{25a^2-4}{2*5a}+\frac{5a}{2}=\frac{2-25a^2+4+25a^2}{10a}=\frac{6}{10a}=\frac{3}{5a}$
При a= $\frac{1}{3}$
$\frac{3}{\frac{5}{3}} =\frac{9}{5}=1 \frac{4}{5} =1,8$

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