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veres2000
@veres2000
September 2021
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sedinalana
Verified answer
12+4x-x²≥0
x²-4x-12≤0
x1+x2=4 U x1*x2=-12
x1=-2 U x2=6
-2≤x≤6
5x²+5x>0
5x(x+1)>0
x=0 U x=-1
x<-1 U x>0
x∈[-2;-1) U (0;6]
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Answers & Comments
Verified answer
12+4x-x²≥0x²-4x-12≤0
x1+x2=4 U x1*x2=-12
x1=-2 U x2=6
-2≤x≤6
5x²+5x>0
5x(x+1)>0
x=0 U x=-1
x<-1 U x>0
x∈[-2;-1) U (0;6]