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razumnaya02
@razumnaya02
August 2022
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Lojke
Verified answer
2)
45-5x²=0
5(9-x²)=0
5(3²-x²)=0
5(3-x)(3+x)=0
x1=3;x2=-3
3)
5x=2x²
2x²-5x=0
x(2x-5)=0
x1=0; 2x-5=0; 2x=5; x2=2.5
4)
3x²+8x-3=0
Д=64+36=100
x1,2= (-8+-√100) / 6
x1=(-8+10)/6=2/6=1/3
x2=(-8-10)/6=-18/6=-3
5)
(х²+1)/5=2х/3
(х²+1)/5-2х/3=0
(3(x²+1)-5(2x))/15=0 |×15
(3(x²+1)-5(2x))=0
3x²+3-10x=0
3x²-10x+3=0
Д=100-36=64
х1=10+8/6=3
х2=10-8/6=1/3
6)
x²+8x+12
x²+8x+12=0
Д=64-4*12=16
x1=(-8+4)/2=-2
x2=(-8-4)/2=-6
Разложим на множители:
x²+8x+12=(х+2)(х+6)
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Answers & Comments
Verified answer
2)45-5x²=0
5(9-x²)=0
5(3²-x²)=0
5(3-x)(3+x)=0
x1=3;x2=-3
3)
5x=2x²
2x²-5x=0
x(2x-5)=0
x1=0; 2x-5=0; 2x=5; x2=2.5
4)
3x²+8x-3=0
Д=64+36=100
x1,2= (-8+-√100) / 6
x1=(-8+10)/6=2/6=1/3
x2=(-8-10)/6=-18/6=-3
5)
(х²+1)/5=2х/3
(х²+1)/5-2х/3=0
(3(x²+1)-5(2x))/15=0 |×15
(3(x²+1)-5(2x))=0
3x²+3-10x=0
3x²-10x+3=0
Д=100-36=64
х1=10+8/6=3
х2=10-8/6=1/3
6)
x²+8x+12
x²+8x+12=0
Д=64-4*12=16
x1=(-8+4)/2=-2
x2=(-8-4)/2=-6
Разложим на множители:
x²+8x+12=(х+2)(х+6)