№1
а) f'(x)=-2-5x^5
б) f'(x)=(15x³-5x+9x²-3)'=45x²-5+18x
в) f'(x)= (8+x²)'(5-x) - (8+x²)(5-x)' / (5-x)² = 2x(5-x) - (8+x²)×(-1) / (5-x)² = (-x²+10x+8) / (5-x)²
№2
f'(x)=8x³+ 5/2x² - 4
f'(-1) =8×(-1)³ + 5/2×(-1)³ -4 = -8 - 5/2 -4 = -29/2
№3
a) f'(x)= (3 × 1/cos²x - sinx - cosx) =3/cos²x-sinx-cosx
б) f'(x)=(lnx)'×sinx + lnx×(sinx)'=1/x × sinx + lnx × cosx = sinx/x + lnxcosx
в) f'(x)= (9/2 log(2) х + 53/10 - 3х⁴)' = 9/2ln(2)x - 12x³
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Answers & Comments
№1
а) f'(x)=-2-5x^5
б) f'(x)=(15x³-5x+9x²-3)'=45x²-5+18x
в) f'(x)= (8+x²)'(5-x) - (8+x²)(5-x)' / (5-x)² = 2x(5-x) - (8+x²)×(-1) / (5-x)² = (-x²+10x+8) / (5-x)²
№2
f'(x)=8x³+ 5/2x² - 4
f'(-1) =8×(-1)³ + 5/2×(-1)³ -4 = -8 - 5/2 -4 = -29/2
№3
a) f'(x)= (3 × 1/cos²x - sinx - cosx) =3/cos²x-sinx-cosx
б) f'(x)=(lnx)'×sinx + lnx×(sinx)'=1/x × sinx + lnx × cosx = sinx/x + lnxcosx
в) f'(x)= (9/2 log(2) х + 53/10 - 3х⁴)' = 9/2ln(2)x - 12x³