Помогите решить Пожалуйста. Created by ангел33. matematika-ru

Помогите решить Пожалуйста...

vmaluga2011 (х+2)/(х-2) + (х-2)/(х+2) = 2 1/6
знаменатели≠0 ⇒ х≠2 ; х≠-2
((х+2)(х+2) + (х-2)(х-2)) / (х-2)(х+2) = 13/6
( (х+2)² + (х-2)² ) / (х² -2²) = 13/6
(х²+2х +4 + х² -2х +4 ) /(х²-4) = 13/6
(2х² +8)/ (х²-4) = 13/6
6(2х²+8) = 13(х²-4)
12х² +48 = 13х² - 52
12х² -13х² = -52-48
-х²=-100 |*(-1)
x²=100
x₁= 10
x₂=-10

(x²+x-12)/(x²+8x +16 ) = (x²-3x +4x-12) /(x²+2*4x +4²) =
=(x(x-3) +4(x-3))/ (x+4)² = ((x+4)(x-3) ) / (x+4)² =
= (x-3)/(x+4)

0 votes Thanks 0

zhenyaM2002

Verified answer

(х+2)/(х-2)+(х-2)/(х+2)=2 1/6 (умножим на 6(х-2)(х+2))
6(х+2)(х+2)+6(х-2)(х-2)=13(х-2)(х+2)
6(х2+2х+2х+4)+6(х2-2х-2х+4)=13(х2+2х-2х-4)
6х2+24х+24+6х2-24х+24=13х2-52
х2-100=0
х2=100
х(1)=-10
х(2)=10

2 votes Thanks 1

Answers & Comments

Verified answer

рекомендуемые вопросы

Helpful Links

Helpful Social