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kisakiss2
@kisakiss2
August 2022
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Simba2017
8а=2b обозначим, тогда
сos2b/(cosb+sinb)=cos^2 b-sin^2 b/(cosb+sinb)=cosb-sinb=cos4a-sin4a
дальше раскрывать я думаю не стоит
1 votes
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sedinalana
Cos8a/(cos4a+sin4a)=(cos²4a-sin²4a)/(cos4a+sin4a)=
=(cos4a-sin4a)(cos4a+sin4a)=cos4a-sin4a
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Answers & Comments
сos2b/(cosb+sinb)=cos^2 b-sin^2 b/(cosb+sinb)=cosb-sinb=cos4a-sin4a
дальше раскрывать я думаю не стоит
=(cos4a-sin4a)(cos4a+sin4a)=cos4a-sin4a