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nika2604201
@nika2604201
July 2022
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W1NSON
1
ОДЗ
x+2>0⇒x>-2
x>0
2x+1>0⇒x>-0,5
x∈(0;∞)
log(3)[x(x+2)]<log(3)(2x+1)
x²+2x<2x+1
x²-1<0
(x-1)(x+1)<0
x=1 x=-4
-1<x<1
x⇒(0;1)
2
ОДЗ
49-x²≥0
(7-x)(7+x)≥0
x=7 x=-7
-7≤x≤7
x>0
x∈(0;7]
√(49-x²)≥0⇒log(5)x/(x-5)≥0
1)log(5)x≥0⇒x≥1
x-5>0⇒x>5
5<x≤7
2)log(5)x≤0⇒x≤1
x-5<0⇒x<5
0<x≤1
x∈(0;1] U (5;7]
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Answers & Comments
ОДЗ
x+2>0⇒x>-2
x>0
2x+1>0⇒x>-0,5
x∈(0;∞)
log(3)[x(x+2)]<log(3)(2x+1)
x²+2x<2x+1
x²-1<0
(x-1)(x+1)<0
x=1 x=-4
-1<x<1
x⇒(0;1)
2
ОДЗ
49-x²≥0
(7-x)(7+x)≥0
x=7 x=-7
-7≤x≤7
x>0
x∈(0;7]
√(49-x²)≥0⇒log(5)x/(x-5)≥0
1)log(5)x≥0⇒x≥1
x-5>0⇒x>5
5<x≤7
2)log(5)x≤0⇒x≤1
x-5<0⇒x<5
0<x≤1
x∈(0;1] U (5;7]