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milashkavera
@milashkavera
August 2022
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помогите решить пожалуйста!!!очень срочно!!!!
Найдите корень уравнения
log2
(4−x) =8
.
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belcatya
Log₂(4−x) =8
log₂(4−x) =
8log₂2
4-х=2 в восьмой степени
4-х=256
х=-252
1 votes
Thanks 2
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Answers & Comments
log₂(4−x) =8log₂2
4-х=2 в восьмой степени
4-х=256
х=-252