1) 4/b + 4 = (4 + 4b)/b

2) (64b² + 128b + 64)/b : (4 + 4b)/b = (64(b + 1)²)/b * b/(4 + 4b) = (64(b + 1)² * b)/(b * 4(1 + b)) = 16(b + 1)

при b = -15/16

16 * (-15/16 + 1) = 16 * 1/16 = 1

Ответ: 1.

(64b²+128b+64)/b ÷ ((4/b)+4)

1) ( 4/b) + 4 = (4+4b)/b

2) (64b²+128b+64)/b × b/(4+4b) = (64b²+128b+64) / (4+4b) = (64(b²+2b+1)) / (4(1+b)) = 16(b+1)² / (b+1) = 16(b+1) = 16×((-15/16)+1) = 16×(1/16) = 1

Ответ : 1