Home
О нас
Products
Services
Регистрация
Войти
Поиск
reallmax15
@reallmax15
August 2022
1
1
Report
Помогите решить
Производная функции u = x(y^2) - y\sqrt z в точке А(1;-2;1) по направлению к точке В(4;-2;5) равна
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
IrkaShevko
Verified answer
Du/dx = y²
du/dy = 2xy - 1/√z
du/dz = 0,5/√z³
grad(u) в A = (-2)²*i + (2*1*(-2) - 1/√1)*j + (0,5/√1)*k = 4i - 5j + 0,5k
du/dB = du/dx * cosα + du/dy * cosβ + du/dz * cosγ
|B| = √(16 + 4 + 25) = √45 = 3√5
cosα = 4/3√5 = 4√5/15
cosβ = -2/3√5 = -2√5/15
cosγ = 5/3√5 = √5/3
du/dB = 4*4√5/15 + 5*2√5/15 + 0,5*√5/3 = (16√5 + 10√5 + 2,5√5)/15 = 28,5√5/15 = 1,9√5
Ответ: 1,9√5
1 votes
Thanks 0
More Questions From This User
See All
reallmax15
July 2022 | 0 Ответы
kak raskolnikov gotovilsya k ubijstvu roman prestuplenie i nakazanie
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите решить Производная функции u = x(y^2) - y\sqrt z в точке А(1;-2;1) по н..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Du/dx = y²du/dy = 2xy - 1/√z
du/dz = 0,5/√z³
grad(u) в A = (-2)²*i + (2*1*(-2) - 1/√1)*j + (0,5/√1)*k = 4i - 5j + 0,5k
du/dB = du/dx * cosα + du/dy * cosβ + du/dz * cosγ
|B| = √(16 + 4 + 25) = √45 = 3√5
cosα = 4/3√5 = 4√5/15
cosβ = -2/3√5 = -2√5/15
cosγ = 5/3√5 = √5/3
du/dB = 4*4√5/15 + 5*2√5/15 + 0,5*√5/3 = (16√5 + 10√5 + 2,5√5)/15 = 28,5√5/15 = 1,9√5
Ответ: 1,9√5