f '(x) = (3lnx² + cos(sinx) - √(x- 1))' = 6x/x² - sin(sinx)·cosx - 1/(2√(x- 1)) = 6/x - sin(sinx)·cosx - 1/(2√(x- 1))
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f '(x) = (3lnx² + cos(sinx) - √(x- 1))' = 6x/x² - sin(sinx)·cosx - 1/(2√(x- 1)) = 6/x - sin(sinx)·cosx - 1/(2√(x- 1))