x2 + 5x - 6 = 0
a = 1 b = 5 c = ‑ 6
D = b² - 4 * a * c
D = (5)² - 4 * 1 * (‑ 6) = 25 + 24 = 49
D > 0 => x1,2 =
-b ±
√
D
2 * a
x1,2 =
‑ 5 ±
49
2 * 1
=
‑ 5 ± 7
2
x1 =
‑ 5 - 7
‑ 12
= ‑ 6
x2 =
‑ 5 + 7
= 1
x1 = ‑ 6
x2 = 1
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Answers & Comments
x2 + 5x - 6 = 0
a = 1 b = 5 c = ‑ 6
D = b² - 4 * a * c
D = (5)² - 4 * 1 * (‑ 6) = 25 + 24 = 49
D > 0 => x1,2 =
-b ±
√
D
2 * a
x1,2 =
‑ 5 ±
√
49
2 * 1
=
‑ 5 ± 7
2
x1 =
‑ 5 - 7
2
=
‑ 12
2
= ‑ 6
x2 =
‑ 5 + 7
2
=
2
2
= 1
x1 = ‑ 6
x2 = 1