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Kristina162000
@Kristina162000
July 2022
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Помогите решить ,расписав по действиям
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((sin a - cos a)^2 - 1)(1 + tg^2 a) + 2ctg(pi/2 - a) =
= (sin^2 a - 2sin a*cos a + cos^2 a - 1)*1/cos^2 a + 2tg a =
= (1 - 2sin a*cos a - 1) / cos^2 a + 2tg a = -2sin a*cos a/cos^2 a + 2tg a =
= -2sin a/cos a + 2tg a = -2tg a + 2tg a = 0
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Answers & Comments
Verified answer
((sin a - cos a)^2 - 1)(1 + tg^2 a) + 2ctg(pi/2 - a) == (sin^2 a - 2sin a*cos a + cos^2 a - 1)*1/cos^2 a + 2tg a =
= (1 - 2sin a*cos a - 1) / cos^2 a + 2tg a = -2sin a*cos a/cos^2 a + 2tg a =
= -2sin a/cos a + 2tg a = -2tg a + 2tg a = 0