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dotacool98
@dotacool98
July 2022
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Помогите решить! Решение на листочке
sin3x-sinx=0
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Answers & Comments
Lesben
Sin3x-sinx=0
2.cos2x.sinx=0
cos2x.sinx=0
a)cos2x=0, 2x=π/2+k.π , x= π/4+k.π/2
b)sinx=0, x=k.π
k∈Z
( sinα-sinβ=2.cos((α+β)/2).sin((α-β)/2)
1 votes
Thanks 1
dotacool98
а нижнии точки это умножение?
Lesben
Da,naprimer: 2.3=6, 14.3=42, 8.4=32 itd.
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Answers & Comments
2.cos2x.sinx=0
cos2x.sinx=0
a)cos2x=0, 2x=π/2+k.π , x= π/4+k.π/2
b)sinx=0, x=k.π
k∈Z
( sinα-sinβ=2.cos((α+β)/2).sin((α-β)/2)