Помогите решить с 1 по 9. Created by Filil. algebra-ru

Помогите решить с 1 по 9...

amin07am

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sedinalana 1
3(p+2q)/p(p+2q)=3/p
2
3x(x²+y²)/[6y(x²+y²)]=x/(2y)
3
(k-4)²/(k-4)=k-4
4
(p-2q)/(p-2q)²=1/(p-2q)
5
(2m-3)/[(2m-3)(2m+3)]=1/(2m+3)
6
(9+12z+16z²)/[(3-4z)(9+12z+16z²)=1/(3-4z)
7
(5+2m)/[(5+2m)(25-10m+4m²)]=1/(25-10m+4m²)
8
(2m-3n)(2m+3n)/(2m-3n)²=(2m+3n)/(2m-3n)
9
(s+6t)²/[(S-6t)(s+6t)]=(s+6t)/(s-6t)

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