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Sasha89044
@Sasha89044
November 2021
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Помогите решить с полным доказательством
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sangers1959
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Треугольники ВЕА и СFD равны, так как: AB=CD, ∠BAD=∠CDA, ∠BEA=∠CFD ⇒ АЕ=FD
AE+EF+FD=b
2*AE+a=b
AE=(b-a)/2
AF=AE+EF=AE+a=(b-a)/2+a=(b-a+2a)/2=(a+b)/2.
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Answers & Comments
Verified answer
Треугольники ВЕА и СFD равны, так как: AB=CD, ∠BAD=∠CDA, ∠BEA=∠CFD ⇒ АЕ=FDAE+EF+FD=b
2*AE+a=b
AE=(b-a)/2
AF=AE+EF=AE+a=(b-a)/2+a=(b-a+2a)/2=(a+b)/2.