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7Kluke7
@7Kluke7
July 2022
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Помогите решить самостоятельную , даю 35б 7 класс
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гюйс
Verified answer
1. а(х-у)
2. 3х+1
3. 3у(у+5)
4. .....=(5b - c)(5b+c)
5. .....а² - 8а+16=(а-4)²
6. .....=4n(m-k) - (k-m)=4n(m-k)+(m-k)=(m-k)(4n+1)
7. ...=5у(х-2)-х(х-2)=(х-2)(5у-х)
при х=102, у= - 4/5
(102 -2)( -5*4/5 - 102)=100*( - 106)= - 10600
8. ....=2а(2а+1) - b(b+1)
9. ......=х³у+
4х²у
+
х²у²
+
4ху² - х²у² - 4х²у
- ху³
- 4ху²
=х³у - ху³
10. ......=6^(26) *(6² -1)=6^(26) * 35=2^(26) * 3^(26)*35=2^(26) * 3^(25)*3*35=
2^(26) * 3^(25)*105
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Answers & Comments
Verified answer
1. а(х-у)2. 3х+1
3. 3у(у+5)
4. .....=(5b - c)(5b+c)
5. .....а² - 8а+16=(а-4)²
6. .....=4n(m-k) - (k-m)=4n(m-k)+(m-k)=(m-k)(4n+1)
7. ...=5у(х-2)-х(х-2)=(х-2)(5у-х)
при х=102, у= - 4/5
(102 -2)( -5*4/5 - 102)=100*( - 106)= - 10600
8. ....=2а(2а+1) - b(b+1)
9. ......=х³у+4х²у+х²у²+4ху² - х²у² - 4х²у - ху³ - 4ху²=х³у - ху³
10. ......=6^(26) *(6² -1)=6^(26) * 35=2^(26) * 3^(26)*35=2^(26) * 3^(25)*3*35=2^(26) * 3^(25)*105