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jjlk
@jjlk
July 2022
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помогите решить
sin x - √3cos x = 2
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KuOV
Verified answer
Разделим на 2 обе части.
1/2 sinx - √3/2 cosx = 1
sinx · cos(π/3) - sin(π/3) · cosx = 1
sin(x - π/3) = 1
x - π/3 = π/2 + 2πn
x = 5π/6 + 2πn
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Answers & Comments
Verified answer
Разделим на 2 обе части.1/2 sinx - √3/2 cosx = 1
sinx · cos(π/3) - sin(π/3) · cosx = 1
sin(x - π/3) = 1
x - π/3 = π/2 + 2πn
x = 5π/6 + 2πn