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TeroZord
@TeroZord
July 2022
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Помогите решить! sin,cos, tg
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Удачник66
0 < a < Π/2, значит, sin a > 0; cos a > 0
sin a = 0,8
cos^2 a = 1 - sin^2 a = 1 - 0,64 = 0,36
cos a = 0,6
tg a = sin a/cos a = 0,8/0,6 = 4/3
ctg a = 1/tg a = 3/4
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Answers & Comments
sin a = 0,8
cos^2 a = 1 - sin^2 a = 1 - 0,64 = 0,36
cos a = 0,6
tg a = sin a/cos a = 0,8/0,6 = 4/3
ctg a = 1/tg a = 3/4