Verified answer

x² + x - 2 > 0

|x-2|≤5

=====

x² + x - 2 = 0

D = 1+8 = 9

x12=(-1 +- 3)/2 = -2  1

(x-1)(x+2)>0

++++++++(-2) -------- (1) ++++++++

x∈(-∞  -2) U ( 1 +∞)

|x - 2| ≤5

-5 ≤ x - 2 ≤ 5

-3 ≤ x ≤ 7

x∈[-3  7]  пересекаем с x∈(-∞  -2) U ( 1 +∞)

Ответ x∈[-3 , -2) U (1,  7]