Помогите решить систему уравнений: 2xy+yz=27; 3yz-2zx=25; xz-xy=4
2xy+yz=27
3yz-2xz=25
xz-xy=4
xz=4+xy
3yz-2(4+xy)=25
3yz-2xy=33
4yz=60 yz=15
xy=6
xz=10
y=15/z 15x/z=6 xz=10
x=6/15*z x=10/z
6/15*z =10/z
(6/15*z^2-10)/z=0
0.4*z^2-10=0
z^2=25
z=5 z=-5
x=2 x=-2
y=3 y=-3
x=2 y=3 z=5
x=-2 y=-3 z=-5
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Verified answer
2xy+yz=27
3yz-2xz=25
xz-xy=4
xz=4+xy
3yz-2(4+xy)=25
3yz-2xy=33
3yz-2xy=33
2xy+yz=27
4yz=60 yz=15
xy=6
xz=10
y=15/z 15x/z=6 xz=10
x=6/15*z x=10/z
6/15*z =10/z
(6/15*z^2-10)/z=0
(6/15*z^2-10)/z=0
0.4*z^2-10=0
z^2=25
z=5 z=-5
x=2 x=-2
y=3 y=-3
x=2 y=3 z=5
x=-2 y=-3 z=-5