Помогите решить систему уравнений методом подстановки:
1)4х-3у=-1
х-5у=4
2)2х-5у=-7
х-3у=-5
3)3х-5у=16
2х+у=2
4)2х+5у=-7
3х-у=15
5)2х-3у=5
х-6у=-2
6)5х-4у=12
х-5у=-6
ПРОШУ ПОМОГИТЕ ОЧЕНЬ СРОЧНО
1)4х-3у=-1
х-5у=4
2)2х-5у=-7
х-3у=-5
3)3х-5у=16
2х+у=2
4)2х+5у=-7
3х-у=15
5)2х-3у=5
х-6у=-2
6)5х-4у=12
х-5у=-6
ПРОШУ ПОМОГИТЕ ОЧЕНЬ СРОЧНО
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Verified answer
1) x = 4 + 5y4(4 + 5y) - 3y = -1
16 + 20y - 3y = -1
17y = -17
y = -1; x = 4 - 5 = -1
2) x = 3y - 5
2(3y - 5) - 5y = -7
6y - 10 - 5y = -7
y = 3; x = 9 - 5 = 4
3) y = 2 - 2x
3x - 5(2 - 2x) = 16
3x - 10 + 10x = 16
13x = 26
x = 2; y = 2 - 4 = -2
4) y = 3x - 15
2x + 5(3x - 15) = -7
2x + 15x - 75 = -7
17x = 68
x = 4; y = 12 - 15 = -3
5) x = 6y - 2
2(6y - 2) - 3y = 5
12y - 4 - 3y = 5
9y = 9
y = 1; x = 6 - 2 = 4
6) x = 5y - 6
5(5y - 6) - 4y = 12
25y - 30 - 4y = 12
21y = 42
y = 2; x = 10 - 6 = 4