Ответ:
2(x−7y+3z) = 2x−14y+62
−7(5−a−4b) = −35+7a+28b
−1,2(c−8d+6d) = −1,2(c−2d) = −1,2c+2,4d
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Ответ:
2(x−7y+3z) = 2x−14y+62
−7(5−a−4b) = −35+7a+28b
−1,2(c−8d+6d) = −1,2(c−2d) = −1,2c+2,4d