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korobeynikov191
@korobeynikov191
July 2022
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Помогите решить срочно пж
√x^2-6x-a=x-3
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Gerren
√x^2-6x-a=x-3
возьмем a=0
√x^2-6x=x-3
√x^2=7x-3
x=7x-3
6x-3=0
x=0,5
a<0
√x^2-6x+a=x-3
√x^2=7x-3-a
x=7x-3-a 7x-3-a≥0 -a≥3-7x a≤7x-3
8x-3-a=0
8x=3+a
x=(3+a)/8
x=a+3-7x 7x-3-a≤0 -a≤3-7x a≥7x-3
8x+a+3=0
x=-(a+3)/8
a>0
√x^2-6x+a=x-3
√x^2=6x-3-a
x=7x-3-a 7x-3-a≥0 -a≥3-7x a≤7x-3
8x-3-a=0
x=(3+a)/8
x=a+3-7x a≥3-7x
-8x+a+3=0
x=(a+3)/8
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korobeynikov191
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Answers & Comments
возьмем a=0
√x^2-6x=x-3
√x^2=7x-3
x=7x-3
6x-3=0
x=0,5
a<0
√x^2-6x+a=x-3
√x^2=7x-3-a
x=7x-3-a 7x-3-a≥0 -a≥3-7x a≤7x-3
8x-3-a=0
8x=3+a
x=(3+a)/8
x=a+3-7x 7x-3-a≤0 -a≤3-7x a≥7x-3
8x+a+3=0
x=-(a+3)/8
a>0
√x^2-6x+a=x-3
√x^2=6x-3-a
x=7x-3-a 7x-3-a≥0 -a≥3-7x a≤7x-3
8x-3-a=0
x=(3+a)/8
x=a+3-7x a≥3-7x
-8x+a+3=0
x=(a+3)/8