Помогите решить. Срочно. Created by bogodar. algebra-ru

1)√(4x-11)-x=-2√(4x-11)=x-2ОДЗ{4x-11≥0⇒4x≥11⇒x≥2,75{x-2≥0⇒x≥2x∈[2,75;∞)4x-11=x²-4x+4x²-8x+15=0x1+x2=8 U x1*x2=15x1=3x2=52)√(2x-1)+2=x√(2x-1)=x-2ОДЗ{2x-1≥0⇒2x≥1⇒x≥0,5{x-2≥0⇒x≥2x∈[2;∞)2x-1=x²-4x+4x²-6x+5=0x1+x2=6 U x1*x2=5x1=1 не удов услx2=53)√(x²+3x-3)=2x-3ОДЗ{x²+3x-3≥0 D=9+12=21 ⇒ x≤(-3-√21)/2 U x≥(-3+√21)/2{2x-3≥0⇒2x≥3⇒x≥1,5x∈[1,5;∞)x²+3x-3=4x²-12x+93x²-15x+12=0x²-5x+4=0x1+x2=5 U x1*x2=4x1=1 не удов услx2=44)√(28+x)+x=2√(28+x=2-xОДЗ{28+x≥0⇒x≥-28{2-x≥0⇒x≤2x∈[-28;2]28+x=4-4x+x²x²-5x-24=0x1+x2=5 U x1*x2=-24x1=-3x2=8 Реклама Реклама Новые вопросы в Алгебра Помогите пожалуйста очень срочно заранее спасибо. помогите пожалуйста очень срочно заранее спасибо. помогите пожалуйста только 3 Решите пж даю 40 баллов помогите2) 5y”-у-2=0; найдите p+q если график функции y=x²+px+q с рациональными коэффициентами пересекает ось Ох в точке с абсциссой (√3-1)² Представьте число 20 в виде дроби со знаменателем 18 Найдите области определения функций:1) y = - 21/√x-172) y = - x/√36-1,8x Срочно надо……….))))) 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Помогите решить. Срочно...

bogodar @bogodar

September 2021 1 29 Report

Помогите решить. Срочно

Answers & Comments

sedinalana

Verified answer

1)√(4x-11)-x=-2
√(4x-11)=x-2
ОДЗ
{4x-11≥0⇒4x≥11⇒x≥2,75
{x-2≥0⇒x≥2
x∈[2,75;∞)
4x-11=x²-4x+4
x²-8x+15=0
x1+x2=8 U x1*x2=15
x1=3
x2=5
2)√(2x-1)+2=x
√(2x-1)=x-2
ОДЗ
{2x-1≥0⇒2x≥1⇒x≥0,5
{x-2≥0⇒x≥2
x∈[2;∞)
2x-1=x²-4x+4
x²-6x+5=0
x1+x2=6 U x1*x2=5
x1=1 не удов усл
x2=5
3)√(x²+3x-3)=2x-3
ОДЗ
{x²+3x-3≥0 D=9+12=21 ⇒ x≤(-3-√21)/2 U x≥(-3+√21)/2
{2x-3≥0⇒2x≥3⇒x≥1,5
x∈[1,5;∞)
x²+3x-3=4x²-12x+9
3x²-15x+12=0
x²-5x+4=0
x1+x2=5 U x1*x2=4
x1=1 не удов усл
x2=4
4)√(28+x)+x=2
√(28+x=2-x
ОДЗ
{28+x≥0⇒x≥-28
{2-x≥0⇒x≤2
x∈[-28;2]
28+x=4-4x+x²
x²-5x-24=0
x1+x2=5 U x1*x2=-24
x1=-3
x2=8