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zzzAAAFFF
@zzzAAAFFF
July 2022
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Abilay1411
1) (x^3-4)'=3x^2
2) (1/x + 2x)'= -1/x^2 + 2
3) (5x^5-
)' 25x^4 - 1/2*
4) (1/2 * x^2 + 4
- 2/x)' = x + 2/
+ 2/x^2
5) ((3x+7)(7x^3+5x-4))'=3(7x^3+5x-4)+(21x^2+5)(3x+7)=21x^3+15x-12+63x^3+147x^2+15x+35= 84x^3+147x^2+30x+47
6)
=
1) (x^5+1)'=5x^4
2) (-1/x - 3x)'= 1/x^2-3
3) (4x^4 +
)= 16x^3 + 1/2*
4) (1/3 * x^3 - 2*
+5/x)'=x^2 - 1/
- 5/x^2
5) ((5x-4)(2x^4-7x+1))'=5(2x^4-7x+1)+(8x^3-7)(5x-4)=10x^4-35x+5+40x^4-32x^3-35x+28=50x^4-32x^3-70x+33
6)
5 votes
Thanks 4
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Answers & Comments
2) (1/x + 2x)'= -1/x^2 + 2
3) (5x^5- )' 25x^4 - 1/2*
4) (1/2 * x^2 + 4 - 2/x)' = x + 2/ + 2/x^2
5) ((3x+7)(7x^3+5x-4))'=3(7x^3+5x-4)+(21x^2+5)(3x+7)=21x^3+15x-12+63x^3+147x^2+15x+35= 84x^3+147x^2+30x+47
6) =
1) (x^5+1)'=5x^4
2) (-1/x - 3x)'= 1/x^2-3
3) (4x^4 + )= 16x^3 + 1/2*
4) (1/3 * x^3 - 2* +5/x)'=x^2 - 1/ - 5/x^2
5) ((5x-4)(2x^4-7x+1))'=5(2x^4-7x+1)+(8x^3-7)(5x-4)=10x^4-35x+5+40x^4-32x^3-35x+28=50x^4-32x^3-70x+33
6)