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Школьнаялалка
@Школьнаялалка
July 2022
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au456
Verified answer
Sin(a-b)=sin a cos b - cos a sin b
на заданных интервалах sin > 0 cos < 0
cos a =√((1- sin a )^2)= -4/5
аналогично соs b = - 12/13
sin(a-b)= -3/5*12/13+4/5*5/13=-36/65+20/65=-16/65
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Answers & Comments
Verified answer
Sin(a-b)=sin a cos b - cos a sin bна заданных интервалах sin > 0 cos < 0
cos a =√((1- sin a )^2)= -4/5
аналогично соs b = - 12/13
sin(a-b)= -3/5*12/13+4/5*5/13=-36/65+20/65=-16/65