Home
О нас
Products
Services
Регистрация
Войти
Поиск
pestov2000
@pestov2000
July 2022
1
2
Report
помогите решить, срочно!
sin4x=3cos2x
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
kratgv
Verified answer
sin4x=3cos2x
2·sin2x·cos2x -
3cos2x=0
cos2x·(2·sin2x - 3)=0
cos2x=0 или 2·sin2x - 3=0
2х=П/2+Пк, к∈Z 2·sin2x = 3
x=П/4+П/2·к, к∈Z sin2x =1,5
нет реш
Ответ:П/4+П/2·к, к∈Z
2 votes
Thanks 4
More Questions From This User
See All
pestov2000
July 2022 | 0 Ответы
4 y 2350b58734127e1a794b2f1ee099a7e35 44769
Answer
pestov2000
July 2022 | 0 Ответы
4 y 26a2034528099d1f0955f37f952b82fbf 2693
Answer
pestov2000
July 2022 | 0 Ответы
reshite pozhalujsta 178d8ffde84688febfbfc26c570582734e 75902
Answer
pestov2000
July 2022 | 0 Ответы
2^(sinx)*2^sin3x=16^(cos^2x)...
Answer
pestov2000
July 2022 | 0 Ответы
4 y 24cdd2052fa6464c641b021021feb7a4c 52125
Answer
pestov2000
July 2022 | 0 Ответы
4 y 2
Answer
pestov2000
October 2021 | 0 Ответы
ploshad odnogo kvadrata ravna 768 m a ploshad drugogo 300 dm vo skolko ra
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "помогите решить, срочно!sin4x=3cos2x..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
sin4x=3cos2x2·sin2x·cos2x - 3cos2x=0
cos2x·(2·sin2x - 3)=0
cos2x=0 или 2·sin2x - 3=0
2х=П/2+Пк, к∈Z 2·sin2x = 3
x=П/4+П/2·к, к∈Z sin2x =1,5
нет реш
Ответ:П/4+П/2·к, к∈Z