Решение:
sin²x + √3 · sin x · cos x = 0
sin x · (sin x + √3 · cos x) = 0
2sin x · (0.5 sin x + 0.5 √3 · cos x) = 0
2sin x · sin (π/3 + x) = 0
1)
sin x = 0
x₁ = πn (n ∈ Z)
2)
sin (π/3 + x) = 0
π/3 + x = πk
x₂ = -π/3 + πk (k ∈ Z)
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Решение:
sin²x + √3 · sin x · cos x = 0
sin x · (sin x + √3 · cos x) = 0
2sin x · (0.5 sin x + 0.5 √3 · cos x) = 0
2sin x · sin (π/3 + x) = 0
1)
sin x = 0
x₁ = πn (n ∈ Z)
2)
sin (π/3 + x) = 0
π/3 + x = πk
x₂ = -π/3 + πk (k ∈ Z)