Помогите решить то, что обведено в кружочки.. Created by Б45. algebra-ru

21. 0,3(2х-1)-1,6(х+5)-1,7 ≤ 00,6х-0,3-1,6х-8-1,7 ≤ 0-х ≤ 10х ≥ -10х∈[-10; +∞)∑ цел. отриц. = -10+(-9)+(-8)+(-7)+(-6)+(-5)+(-4)+(-3)+(-2)+(-1) = -55Ответ: 2)22. 2х-4 /√2 + 2√2 - х(√2-3) < 1,82х-4+4-2х+3√2х < 1,8√23√2х < 1,8√23х < 1,8х < 0,6х∈(-∞; 0,6)на промежутке [-3; 3] целые решения нашего неравенства это: -3; -2; -1; 0 - четыре решенияОтвет: 3)24. {1 < 3 - x/5 < 3{(3√3-6)(x-4) ≥ 3√3-6{-2 < -x/5 < 0{x-4 ≥ 1{-10 < -x < 0{x ≥ 5{0 < x < 10{x ≥ 5x∈[5; 10)∑ целых решений = 5+6+7+8+9 = 35Ответ: 2) Реклама Реклама Новые вопросы в Алгебра ПОМОГИТЕ ПО АЛГЕБРЕ!! Решите уравнение 2cos^2 x < sqrt(2) + 2sin^2 x Вычислить определенный интеграл дам 30 баллов Уравнение x2+10x−3=0 является приведённым неприведённым помогите пж даю 50 баллов помогите пж даю 50 баллов найти производную срочно полный разбор сделайте , а не сразу ответ решите пожалуйста, дам 100 баллов!!! постройте график функции обратной данной у=√х-2 +3 постройте график функции, обратной данной у=корень х-2 - это под корнем +3 Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Помогите решить то, что обведено в кружочки...

Б45 @Б45

December 2021 1 9 Report

Помогите решить то, что обведено в кружочки.

Answers & Comments

ВикаВикторовна

Verified answer

21. 0,3(2х-1)-1,6(х+5)-1,7 ≤ 0
0,6х-0,3-1,6х-8-1,7 ≤ 0
-х ≤ 10
х ≥ -10
х∈[-10; +∞)
∑ цел. отриц. = -10+(-9)+(-8)+(-7)+(-6)+(-5)+(-4)+(-3)+(-2)+(-1) = -55
Ответ: 2)

22. 2х-4 /√2 + 2√2 - х(√2-3) < 1,8
2х-4+4-2х+3√2х < 1,8√2
3√2х < 1,8√2
3х < 1,8
х < 0,6
х∈(-∞; 0,6)
на промежутке [-3; 3] целые решения нашего неравенства это: -3; -2; -1; 0 - четыре решения
Ответ: 3)

24. {1 < 3 - x/5 < 3
{(3√3-6)(x-4) ≥ 3√3-6

{-2 < -x/5 < 0
{x-4 ≥ 1

{-10 < -x < 0
{x ≥ 5

{0 < x < 10
{x ≥ 5

x∈[5; 10)
∑ целых решений = 5+6+7+8+9 = 35
Ответ: 2)