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Dreymers
@Dreymers
July 2022
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Помогите решить тригонометрическое уравнение)
sinx+cosx=√2
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Dимасuk
Verified answer
Sinx + cosx = √2
Возведем в квадрат:
sin²x + 2sinxcosx + cos²x = 2
1 + 2sinxcosx = 2
sin2x = 1
2x = π/2 + 2πn, n ∈ Z
x = π/4 + 2πn, n ∈ Z.
2 votes
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Answers & Comments
Verified answer
Sinx + cosx = √2Возведем в квадрат:
sin²x + 2sinxcosx + cos²x = 2
1 + 2sinxcosx = 2
sin2x = 1
2x = π/2 + 2πn, n ∈ Z
x = π/4 + 2πn, n ∈ Z.