sinα = 3/5
sin²α = 9/25
cos²α = 1 - sin²α = 1 - 9/25 = 16/25
cosα = -4/5, так как α ∈ (π/2;π)
tgα = sinα/cosα = (3/5)/(-4/5) = -3/4
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
sinα = 3/5
sin²α = 9/25
cos²α = 1 - sin²α = 1 - 9/25 = 16/25
cosα = -4/5, так как α ∈ (π/2;π)
tgα = sinα/cosα = (3/5)/(-4/5) = -3/4