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ingailm
@ingailm
August 2022
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помогите решить уравнение: (2у+3)в кубе= 4у(2у в квадрате+9)
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Answers & Comments
KatyaZaharovaKZ
(2y + 3)³ = 4y(2y² + 9)
(2y)³ + 3 * (2y)² * 3 + 3 * 2y * 3² + 3³ - 8y³ - 36y = 0
8y³ + 36y² + 54y + 27 - 8y³ - 36y = 0
36y² +18y + 27 = 0
4y² + 2y + 3= 0
D= 2² - 4 * 4 * 3 = 4 - 48 = - 44 < 0
решений нет
1 votes
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Universalka
Verified answer
(2y+3)³=4y(2y²+9)
8y³+36y²+54y+27=8y³+36y
36y²+18y+27=0
4y²+2y+3=0
-2±√2²-4•4•3
y=___________
2•4
-2±√44
y=___________
8
как-то так, я пыталась
0 votes
Thanks 0
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Answers & Comments
(2y)³ + 3 * (2y)² * 3 + 3 * 2y * 3² + 3³ - 8y³ - 36y = 0
8y³ + 36y² + 54y + 27 - 8y³ - 36y = 0
36y² +18y + 27 = 0
4y² + 2y + 3= 0
D= 2² - 4 * 4 * 3 = 4 - 48 = - 44 < 0
решений нет
Verified answer
(2y+3)³=4y(2y²+9)8y³+36y²+54y+27=8y³+36y
36y²+18y+27=0
4y²+2y+3=0
-2±√2²-4•4•3
y=___________
2•4
-2±√44
y=___________
8
как-то так, я пыталась