sedinalana

Verified answer

(x-3)(√2-1)/[(√2+1)(√2-1)]+x(√3-√2)/[(√3+√2)(√3-√2)]=(√3-2)x-4-4√2
(x-3)(√2-1)/(2-1)+x(√3-√2)/(3-2)=(√3-2)x-4-4√2
x√2-x-3√2+3+x√3-x√2=x√3-2x-4-4√2
-x+x√3-x√3+2x=-4-4√2+3√2-3
x=-7-√2