Verified answer

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Делим всё на 2

√3/2sinx-1/2cosx=-√3/2

cos(π/6) =√3/2

sin(π/6)=1/2

sinx*cos(π/6) -cosx*sin(π/6)=-√3/2

sin(x-π/6)=-√3/2

x-π/6=-(-1)ⁿπ/3+2πn

x=π/6-(-1)ⁿπ/3+2πn,   n∈Z