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nikolay1602
@nikolay1602
November 2021
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Помогите решить уравнение, пожалуйста...
a) (x+2) (x-1)=0; е) 5z(z+1) (3z-17)=0
b) (z-5) (2z+8)=0; ж) t⁴ =0
в) -3х(0,6x-12) =0; з) (3х+2)² =0
г) (5-2t) (7+5t)=0; и) x² (x-3) (x+6)=0
д) ( y-3) (y+4) (3y-5)=0; к) y³ (y-1)² (y+1)=0
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