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ada200030
@ada200030
June 2022
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hovsep50
4·(x-4)+11·(x-11)=2·(x-11)·(x-4)
4x-16+11x-121=2·(x²-11x-4x+44)
15x-137=2x²-30x+88
2x²-45x+225=0
x=[45+/-√(2025-4·2·225)]/4 = (45+/-√225)/4 = (45+/-15)/4
x1=(45-15)/4=7,5
x2=(45+15)/4=15
Ответ: 7,5 ; 15
2 votes
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ada200030
спасибо большое
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Answers & Comments
4x-16+11x-121=2·(x²-11x-4x+44)
15x-137=2x²-30x+88
2x²-45x+225=0
x=[45+/-√(2025-4·2·225)]/4 = (45+/-√225)/4 = (45+/-15)/4
x1=(45-15)/4=7,5
x2=(45+15)/4=15
Ответ: 7,5 ; 15