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deevil
@deevil
July 2022
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Помогите решить!!! Уравнение Срочно!!!!!
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Санечка69
Verified answer
А) домножим на число 21, чтобы "избавиться" от дробей:
7(10 + 2х) = 4 · 3 - 21х
70 + 14х = 12 - 21х
14х + 21х = 12 - 70
35х = -58
х = - 58/35 = -1 целая 23/35
б) sin2x = √3sinx
2sinx · cosx - √3sinx = 0
sinx(2cosx - √3) = 0
sinx = 0 или
2cosx - √3 = 0
x = πn, n ∈ Z cosx = √3/2
x = +-π/6 + 2πk, k ∈ Z
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AnonimusPro
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Ответ: x=
Ответ:
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Answers & Comments
Verified answer
А) домножим на число 21, чтобы "избавиться" от дробей:7(10 + 2х) = 4 · 3 - 21х
70 + 14х = 12 - 21х
14х + 21х = 12 - 70
35х = -58
х = - 58/35 = -1 целая 23/35
б) sin2x = √3sinx
2sinx · cosx - √3sinx = 0
sinx(2cosx - √3) = 0
sinx = 0 или 2cosx - √3 = 0
x = πn, n ∈ Z cosx = √3/2
x = +-π/6 + 2πk, k ∈ Z
Verified answer
Ответ: x=
Ответ: