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poluektovroman577
@poluektovroman577
July 2022
2
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помогите решить уравнение
-y2 + 3y + 5 = 0;
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sevamalov
Ответ:
1)
Пошаговое объяснение:
1 votes
Thanks 1
evvoronina1
-y² + 3y + 5 = 0
Умножим обе части уравнения на -1:
y² - 3у - 5 = 0
D = 3² - 4•(-5)= 9 + 20 = 29
D = √29
у1 = (3 + √29)/2
у2 = (3 - √29)/2
Проверка
-((у - (3 + √29)/2)((у - (3 -√29)/2)) = 0
-((у - 3/2 - (√29)/2)((у - 3/2 + (√29)/2) = 0
-(y² - 3у/2 - у(√29)/2 -3у/2 + 9/4 + 3(√29)/4+
+ у(√29)/2 - 3(√29)/4 - (√29)(√29)/4) = 0
-(y² - 2•3у/2 + 9/4 - 29/4) = 0
-(y² - 3у - 20/4) = 0
-(y² - 3у - 5) = 0
-y² + 3у + 5 = 0
1 votes
Thanks 0
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Answers & Comments
Ответ:
1)
Пошаговое объяснение:
Умножим обе части уравнения на -1:
y² - 3у - 5 = 0
D = 3² - 4•(-5)= 9 + 20 = 29
D = √29
у1 = (3 + √29)/2
у2 = (3 - √29)/2
Проверка
-((у - (3 + √29)/2)((у - (3 -√29)/2)) = 0
-((у - 3/2 - (√29)/2)((у - 3/2 + (√29)/2) = 0
-(y² - 3у/2 - у(√29)/2 -3у/2 + 9/4 + 3(√29)/4+
+ у(√29)/2 - 3(√29)/4 - (√29)(√29)/4) = 0
-(y² - 2•3у/2 + 9/4 - 29/4) = 0
-(y² - 3у - 20/4) = 0
-(y² - 3у - 5) = 0
-y² + 3у + 5 = 0