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boy2471
@boy2471
July 2022
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Nikst2016
Х•(x+1)•(x-1)(x+2)-24=0
(X^2+x)•(x^2-x+2x-2)-24=0
(X^2+x)•(x^2+x-2)-24=0; x^2+x=t
t•(t-2)-24=0
t^2-2t-24=0
D=4+96=100
t1=(2+10)/2=6
t2=(2-10)/2=-4
X^2+x=6
x^2+x-6=0
D=1+24=25
X1=(-1+5)/2=2
X2=(-1-5)/2=-3
X^2+x=-4
X^2+x+4=0
D=1-8=-7-корней нет
Ответ:2;-3
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Answers & Comments
(X^2+x)•(x^2-x+2x-2)-24=0
(X^2+x)•(x^2+x-2)-24=0; x^2+x=t
t•(t-2)-24=0
t^2-2t-24=0
D=4+96=100
t1=(2+10)/2=6
t2=(2-10)/2=-4
X^2+x=6
x^2+x-6=0
D=1+24=25
X1=(-1+5)/2=2
X2=(-1-5)/2=-3
X^2+x=-4
X^2+x+4=0
D=1-8=-7-корней нет
Ответ:2;-3