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Limon93
@Limon93
March 2022
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помогите решить уравнение!!!!!!!
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ShirokovP
Verified answer
√(x^2 - 1 ) = 1 - x
ОДЗ
x ≤ 1
x^2 - 1 = (x - 1)^2
(x - 1)(x + 1) - (x - 1)^2 = 0
(x - 1)(x + 1 - (x - 1)) = 0
(x - 1)(x + 1 - x + 1) = 0
(x - 1) *2 = 0
x - 1 = 0
x = 1
Ответ
1
2 votes
Thanks 1
Kixcertborn2
Verified answer
√(x^2-1 ) = 1-x
ODS:
x ≤ 1
x^2-1=(x-1)^2
x^2-1=x^2-2x+1
-1=-2x+1
2x=1+1
2x=2
x=1
0 votes
Thanks 0
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Answers & Comments
Verified answer
√(x^2 - 1 ) = 1 - xОДЗ
x ≤ 1
x^2 - 1 = (x - 1)^2
(x - 1)(x + 1) - (x - 1)^2 = 0
(x - 1)(x + 1 - (x - 1)) = 0
(x - 1)(x + 1 - x + 1) = 0
(x - 1) *2 = 0
x - 1 = 0
x = 1
Ответ
1
Verified answer
√(x^2-1 ) = 1-xODS: x ≤ 1
x^2-1=(x-1)^2
x^2-1=x^2-2x+1
-1=-2x+1
2x=1+1
2x=2
x=1