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лолангрпт
@лолангрпт
August 2022
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помогите решить уравнение(2x-1)^2=2x-1
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русская25
4х^2 - 4x + 1 = 2x - 1
4x^2 - 6x + 2 = 0
D = 36 - 4*4*2 = 36 - 32 = 4; √D = 2
x1 = (6 + 2)/ 8 = 1
x2 = (6 - 2)/8 = 0,5
Ответ: х1 = 1; х2 = 0,5
1 votes
Thanks 1
лолангрпт
спасибо!!!
кляча
Verified answer
(2x-1)² = 2x-1
Обозначим (2x-1) = t, тогда
t² = t
t² - t = 0
t(t-1)=0
t₁=0, t₂= 1
2x-1=0
2x= 1
x₁=0,5
2x-1=1
2x= 2
x₂=1
Ответ: 0,5; 1.
1 votes
Thanks 1
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Answers & Comments
4x^2 - 6x + 2 = 0
D = 36 - 4*4*2 = 36 - 32 = 4; √D = 2
x1 = (6 + 2)/ 8 = 1
x2 = (6 - 2)/8 = 0,5
Ответ: х1 = 1; х2 = 0,5
Verified answer
(2x-1)² = 2x-1Обозначим (2x-1) = t, тогда
t² = t
t² - t = 0
t(t-1)=0
t₁=0, t₂= 1
2x-1=0
2x= 1
x₁=0,5
2x-1=1
2x= 2
x₂=1
Ответ: 0,5; 1.