Sin(x)^2-√3\2cos(x) = 1

-√3/2cos(x) = 1 - sin(x)^2

-√3/2cos(x) - cos(x)^2 = 0

cos(x) * (cos(x)  + √3/2) = 0

cos(x) = 0 или cos(x) = -√3/2

x= π/2 + πn или x= ±5π/6 +2πK Ответ:2