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matthew88
@matthew88
July 2022
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TARTILLO
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12-∛(16y)=∛(32y²)
∛(2y)=t
12-∛(8·2y)=∛[8(2y)²]
12-2t=2t² t² +t-6=0 t1=-3 2y1=-3 y1=-3/2 y1=-1.5 t2=2 2y2=2 y2=1
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Answers & Comments
Verified answer
12-∛(16y)=∛(32y²)∛(2y)=t
12-∛(8·2y)=∛[8(2y)²]
12-2t=2t² t² +t-6=0 t1=-3 2y1=-3 y1=-3/2 y1=-1.5 t2=2 2y2=2 y2=1