Home
О нас
Products
Services
Регистрация
Войти
Поиск
kirillchuyckow
@kirillchuyckow
July 2022
1
6
Report
Помогите решить уравнение...
log6 (x+1) + log6 (2x+1)=1
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
mmb1
Verified answer
log6 (x+1) + log6 (2x+1)=1
x+1>0
x>-1
2x+1>1
x>-1/2
log6 (x+1)(2x+1)=1
()x+1)(2x+1)=6
2x^2+x+2x+1=6
2x^2+3x-5=0
x12=(-3+-корень(9+40))/4=(-5+-7)/4=-3 1/2
-3 не подходит
х=1/2
0 votes
Thanks 0
kirillchuyckow
последние 3 строчки не могу понять...
More Questions From This User
See All
kirillchuyckow
July 2022 | 0 Ответы
proshu umolyayu ochen srochno spasajtesila toka izmenyaetsya otnochitelno uravneni
Answer
kirillchuyckow
July 2022 | 0 Ответы
proshu ochen srochnoradiopriemnik mozhno nastraivat na priem radiovoln ra
Answer
kirillchuyckow
July 2022 | 0 Ответы
zrobiti fonetichnij rozbir i rozbir za budovoyu slova primiskij
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите решить уравнение...log6 (x+1) + log6 (2x+1)=1..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
log6 (x+1) + log6 (2x+1)=1x+1>0
x>-1
2x+1>1
x>-1/2
log6 (x+1)(2x+1)=1
()x+1)(2x+1)=6
2x^2+x+2x+1=6
2x^2+3x-5=0
x12=(-3+-корень(9+40))/4=(-5+-7)/4=-3 1/2
-3 не подходит
х=1/2