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JULIA120203
@JULIA120203
July 2022
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помогите решить уравнение!!!
заранее спасибо)
(2-x)^3+(2-x)^2*x+4(2-x)=0
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kunka01
((2-х)^3+(2-х)х+4)*(2-х)=0
(4-4х+х^2+2х-х^2+4)*(2-х)=0
(8-2х)*(2-х)=0
2(4-х)*(2-х)=0
(4-х)*(2-х)=0
4-х=0
2-х=0
х=4
х=2
ответ:х1=2, х2=4
1 votes
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Answers & Comments
(4-4х+х^2+2х-х^2+4)*(2-х)=0
(8-2х)*(2-х)=0
2(4-х)*(2-х)=0
(4-х)*(2-х)=0
4-х=0
2-х=0
х=4
х=2
ответ:х1=2, х2=4